Answer :
-3030J is w for the expansion of a gas from 15. l to 35. l against a constant external pressure of 1.5 atm
Work = - P.δV …(1)
Where: P is the pressure, and δV is the change in volume.
Given, the external pressure, P = 1.5 atm
The initial volume of the gas = 15 liters
The final volume of the gas = 35 liters
Substituting the given values into the equation (1), we have;
Work = - 1.5 × (35 - 15)
Work = - 1.5 ×20 =-30 atm. L
Work = -30 × 101 = -3030J
The temperature at which a liquid's vapour pressure equals the air pressure surrounding it, turning the liquid into a vapour, is known as a chemical compound's boiling point. When a pure liquid reaches its typical boiling point, vapour bubbles start to develop because the vapour pressure of the liquid equals the external pressure of one atmosphere (1 bar).
what is w for the expansion of a gas from 15. l to 35. l against a constant external pressure of 1.5 atm?
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