Answer :
The probability that a baseball player has exactly 5 hits in his next 7 at bats = 0.0034
In this question we have been given a baseball player has a batting average of 0.19
We need to find the probability that he has exactly 5 hits in his next 7 at bats.
We know that the formula for the binomial distribution:
P(x) = nCx p^x q^(n - x)
From given information:
p = 0.19
q = 1 - p
= 1 - 0.19
= 0.81
n = 7 and x = 5
Using binomial distribution formula the probability would be,
P = nCx p^x q^(n - x)
P = 7C5 * (0.19)^5 * (0.81)^(7 - 5)
P = 21 * (0.19)^5 * (0.81)^2
P = 0.0034
Therefore, the required probability is: 0.0034
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