if one earthquake is 60 times as intense as another, how much larger is its magnitude on the richter scale? (round your answer to one decimal place.)



Answer :

If one earthquake is 60 times as intense as another, magnitude on the richter scale will be 1.6.

There are many natural occurrences, such as natural disasters, that are out of human control.

Earthquakes are one of the most frequent of them and they greatly harm both people and property.

Studying earthquakes is the subject of seismology. Using the Richter scale, earthquake magnitude is determined. Basically, it is calculated using the logarithm of the earthquake's strength (to the base 10) (which is measured using seismograph).

Let's assume that the initial earthquake had an intensity of [tex]I_{1[/tex] and a Richter scale magnitude of [tex]R_{1[/tex].

Similarly let us assume that the second earthquake had an intensity of [tex]I_{2[/tex] and a Richter scale magnitude of [tex]R_{2[/tex].

So, according to the given details [tex]I_{2[/tex] = 60 × [tex]I_{1[/tex]

⇒ [tex]I_{2[/tex] ÷ [tex]I_{1[/tex] = 60

On a Richter scale, the difference between two earthquakes' magnitudes is equal to the logarithm of the ratio of their intensities (to the base 10).

∴ [tex]R_{2[/tex] - [tex]R_{1[/tex] =  [tex]log_{10}[/tex] [tex]I_{2[/tex] ÷ [tex]I_{1[/tex]

= [tex]log_{10}[/tex](60)

= 1.6

Thus the magnitude of the second earthquake will be larger by 1.6 on the Richter scale.

Know more about Richter scale:

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