On solving the provided question, we can that - by the help, of prime factorization, (2h + 1) is one of the factors of the given equation.
All numbers are expressed as prime number products through the method of prime factorization. Let's use the number 20 as an example. We may divide this into two halves. That's 4 multiplied by 5, so. The number 5 is a prime number, too. Not being prime, number four. N = Xa Yb Zc is the generic factorization formula, where a, b, and c stand for the exponential powers of the factors of the factored number.
[tex]-h^2 - 15h - 7\\-(2h^2 + 15h + 7)[/tex]
Solving it by the Prime Factorization,
[tex]-(2h^2 + (14+1)h + 7)\\-(2h^2 + 14h+1h + 7)\\-(2h(h + 7)+1(h + 7))\\-[(2h+7)(h+7)]\\[/tex]
The correct statement is so,
(2h + 1) is one of the factors of the given equation.
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