The age of the husband of the son's mother or son's father is equivalent to 48 years.
Given:
The sum of ages of a family of four is 93 years.
The father is 1⅓ times as old as the wife.
The wife is 6 times as old as the elder one.
The elder son is twice as old as the younger son.
So, let's assume that age of the younger son = x.
Then, according to the given question,
Age of elder son = 2x.
Age of the wife of the son's father or son's mother = 6 * 2x = 12x.
Age of the husband of the son's mother or son's father = 12x * 4/3 = 16x.
Therefore, given the sum of ages of a family of four is 93 years.
Adding all the values of father, mother, and both sons and equating equal to 93 years we get the value of x.
i.e x + 2x + 12x + 16x = 93
31x = 93
x = 3
Putting the value of x we get the age of the father.
Age of the husband of the son's mother or son's father = 16x = 16 * 3 = 48 years.
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