Aquarium 1 contain 4. 6 gallon of water. Louie will begin filling Aquarium 1 at a rate of 1. 2 gallon per minute. Aquarium 2 contain 54. 6 gallon of water. Iaac will begin draining Aquarium 2 at a rate of 0. 8 gallon per minute. After how many minute will both aquarium contain the ame amount of water?



Answer :

The minute will both aquarium contain the ame amount of water this can be determined by forming the linear equation.

What is Linear Equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. Sometimes, the aforementioned is referred to as a "linear equation of two variables," with y and x serving as the variables.

Given :

Aquarium I contains 4.6 gallons of water. Louise will begin filling Aquarium I at a rate of 1.2 gallons per minute.

Aquarium II contains 54.6 gallons of water. Isaac will begin draining Aquarium II at a rate of 0.8 gallons per minute.

The following steps can be used in order to determine the time at which both aquariums contain the same amount of water:

Step 1 - Let the time be 't' at which both aquariums contain the same amount of water.

Step 2 - The amount of water in the Aquarium I at time 't' is given by:

V = 4.6 + 1.2t

where V is the total amount of water at time 't'.

Step 3 - The amount of water in the Aquarium II at time 't' is given by:

V' = 54.6 - 0.8t

where V' is the total amount of water at time 't'.

Step 4 - So, time at which both aquariums contain the same amount of water is given by:

V = V'

4.6 + 1.2t = 54.6 - 0.8t

Step 5 - Simplify the above equation.

50 = 2t

t = 25 minutes

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