A tone i thrown upward with a velocity of 80m/. Find the maximum height reached by the tone. What i the net diplacement and total ditance and total time taken by the tone if it reache back to the hand of the thrower



Answer :

The maximum height reached by the stone is 320m/s.

The net displacement by the stone is 0.

The  total distance by the stone is 640m.

The total time taken by the stone is 8s.

How do you calculate initial velocity using the starting height?

Use the formula V = u + at to determine the time required to reach the maximum height given an initial velocity. Since the object has reached its maximum height and no longer has any initial velocity, you can replace V in the equation with 0.

Initial Velocity u = 80m/s

Final velocity v = 0

Height, s = ?

Using third equation of motion,

v² - u² = 2as

0 - 80² = 2 × 10 × s

s = 6400/20 = 320m/s

The maximum height reached by the stone is 320m/s.

Time taken by the stone,

u - v = a t

80-0 = 10 t

t = 80/10

t = 8s.

Total distance  = upward distance + downwards distance

Total distance  = 2×s

Total distance  = 2×320

Total distance  = 640m

Total Displacement = 0, because the initial and final point is same.

To know more about velocity visit:

https://brainly.com/question/19979064

#SPJ4

Other Questions