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a prankster drops a water balloon from the top of a building. if the balloon is traveling at 29.1 m/s when it strikes a window ledge that is 1.5 m above the ground, how tall is the building? neglect air resistance. a prankster drops a water balloon from the top of a building. if the balloon is traveling at 29.1 m/s when it strikes a window ledge that is 1.5 m above the ground, how tall is the building? neglect air resistance. 40 m 3 m 86 m 45 m



Answer :

Eduard22sly

The height of the building, given that the balloon strikes the window ledge that is 1.5 m above the ground when travelling at 29.1 m/s is 45 m

How do I determine the height of the building?

First, we shall determine the time taken to hit the window. Details below:

  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 29.1 m/s
  • Acceleration due to gravity (g) = 9.81 m/s²
  • Time (t) = ?

v = u + gt

29.1 = 0 + (9.8 × t)

29.1 = 9.8 × t

Divide both sides by 9.8

t = 29.1 / 9.8

t = 2.97 s

Next we shall determine the height from which it fell to the edge of the window. Details below:

  • Time taken (t) = 2.97 s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height from top to window edge (h₁) = ?

h₁ = ½gt²

h₁ = ½ × 9.8 × 2.96²

h₁ = 43.2 m

Finally, we shall determine the height of the building. This is illustrated below:

  • Height from top to window edge (h₁) = 43.2 m
  • Height from window edge to ground (h₂) = 1.5 m
  • Height of building (H) = ?

H = h₁ + h₂

H = 43.2 + 1.5

H = 45 m

Thus, the height of the building is 45 m

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