consider the following figure. a strand has one end tied to a wall, extends across a small fixed pulley, and the other end is tied to a hanging object. the total length of the strand is l = 10.0 m, the mass of the strand is m = 7.00 g, the mass of the hanging object is m = 5.50 kg, and the pulley is a fixed a distance d = 8.00 m from the wall. you pluck the strand between the wall and the pulley and it starts to vibrate. what is the fundamental frequency (in hz) of its vibration?



Answer :

The fundamental frequency (in hz) of its vibration is  878.51 Hz

To determine the fundamental frequency of the vibrating string, we used the equation f = 1/(2π)sqrt(T/m). In this equation, T is the tension of the string, m is the mass of the string and g is the acceleration due to gravity. We calculated T by multiplying the total mass (5.50 kg + 7.00 g) by the acceleration due to gravity (9.81 m/s^2) and the length of the string (10.0 m). We then used this value for T in the equation and the mass of the string (0.007 kg) to calculate the fundamental frequency of the vibrating string (878.51 Hz).

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