cp a 1750 n irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (a and b), each 1.25 m long and weighing 0.290 n. the center of gravity of this beam is one-third of the way along the beam from the end where wire a is attached. if you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? which pulse arrives first? (ignore the effect of the weight of the wires on the tension in the wires.)

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16-12-2022
Physics

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cp a 1750 n irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (a and b), each 1.25 m long and weighing 0.290 n. the center of gravity of this beam is one-third of the way along the beam from the end where wire a is attached. if you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? which pulse arrives first? (ignore the effect of the weight of the wires on the tension in the wires.)

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Qwbox Qwbox · Answer 1 · 2022-12-20T12:28:57-05:00

There will be no time delay in the arrival of the two pulses at the ceiling.

The irregular beam is estimated to weigh one and a half Newtons and is being tested by two strings, each measuring 1.2 meters in length and weighing 0.290 Newtons. At the same moment, the strings are picked.

The object's time to reach the bottom is shown by,

T = √(2H/g)

The relationship shown above shows that the time it takes an object to descend does not rely on the mass of the object, as soon as the springs are removed.

There won't be a time delay between the two pulses' arrivals at the ceiling and the moment at which both ends of the beam reach the ground.

To know more about tension in the string, visit,

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