a car with the windows rolled down is traveling north on a road at a speed of 23.0 m/s. a police car, traveling south at a speed of 38.0 m/s, approaches with its siren producing sound at a frequency of 2400 hz. (enter your answers in hz. assume that the speed of sound in air is 343 m/s.) (a) what frequency does the driver of the car observe as the police car approaches? (enter your answer to the nearest integer.) hz (b) what frequency does the driver of the car detect after the police car passes her? hz (c) repeat parts (a) and (b) for the case when the police car is traveling northbound. while police car overtakes hz after police car passes hz

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16-12-2022
Physics

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a car with the windows rolled down is traveling north on a road at a speed of 23.0 m/s. a police car, traveling south at a speed of 38.0 m/s, approaches with its siren producing sound at a frequency of 2400 hz. (enter your answers in hz. assume that the speed of sound in air is 343 m/s.) (a) what frequency does the driver of the car observe as the police car approaches? (enter your answer to the nearest integer.) hz (b) what frequency does the driver of the car detect after the police car passes her? hz (c) repeat parts (a) and (b) for the case when the police car is traveling northbound. while police car overtakes hz after police car passes hz

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aamirmajeed5100 aamirmajeed5100 · Answer 1 · 2022-12-20T12:29:44-05:00

a) The frequency that the driver of the car observes as the police car approaches is calculated by using the Doppler effect.

The frequency of the sound wave is increased as the source of the sound (the police car) approaches the observer (the driver of the car). The frequency observed by the driver of the car is given by:

f_observed = f_source * (v_source + v_observer) / (v_source - v_observer)

Substituting the given values, we get:

f_observed = 2400 * (38 + 23) / (38 - 23) = 4860 Hz (to the nearest integer).

b) The frequency of the sound wave is decreased as the source of the sound (the police car) moves away from the observer (the driver of the car). The frequency observed by the driver of the car is given by:

f_observed = f_source * (v_source - v_observer) / (v_source + v_observer)

Substituting the given values, we get:

f_observed = 2400 * (38 - 23) / (38 + 23) = 1380 Hz (to the nearest integer).

c)The frequency of the sound wave is decreased as the source of the sound (the police car) approaches the observer (the driver of the car). The frequency observed by the driver of the car is given by:

f_observed = f_source * (v_source - v_observer) / (v_source + v_observer)

Substituting the given values, we get:

f_observed = 2400 * (38 - 23) / (38 + 23) = 1380 Hz (to the nearest integer).

The frequency of the sound wave is increased as the source of the sound (the police car) moves away from the observer (the driver of the car). The frequency observed by the driver of the car is given by:

f_observed = f_source * (v_source + v_observer) / (v_source - v_observer)

Substituting the given values, we get:

f_observed = 2400 * (38 + 23) / (38 - 23) = 4860 Hz (to the nearest integer).

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