Answer :
The two angle of elevation that can be used to hit the target which is 830m away are 10 degrees and 80 Degrees.
The muzzle speed of the gun is 158m/s.
We have to hit a target that is 830m away.
The two angle of elevation can be found by using relation,
R = U²sin2A/g
Where,
Uis the initial velocity,
A is the angle at which the bullet will be launched from the gun and,
g is the acceleration due to gravity.
Putting all the values,
830 = (158)²Sin2A/9.8
Sin2A = 0.32
A = 10°
Now we know that the same range can be reached at the complementary angle,
So, the angle of elevation at which we can hit the target are 10° and 80°.
To know more about range of projectile, visit,
https://brainly.com/question/15502195
#SPJ4
