Answer :
12.28 g of H2 gas occupies 100.0 L at 400.0 K and 2.00 atm. 9.49 g sample of H2 occupy 68.2L at 353 K and 2.00 atm.
Given mass of H2 gas (m1) = 12.28g
Initial volume of H2gas (V1) = 100L
Initial temperature(T1) = 400K
Initial pressure (P1) = 2atm
Changed mass of H2 gas (m2) = 9.49g
Final Temperature (T2) = 353K
Final pressure(P2) = 2atm
Final Volume = V2
We know that from ideal gas law equation: PV =nRT where n = m/M m=molarity which is same
So 2xV2 = 9.39/2 x 0.082 x 353
v2 = 68.2L
It is believed that point particles, which do not interact with one another and travel randomly, create ideal gas. Additionally, it is believed that perfect gas molecules by themselves have no volume.
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