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calculate the centripetal force on the end of a 52.0 m (radius) wind turbine blade that is rotating at 0.42 rev/s. assume the mass is 3.8 kg.



Answer :

Main Answer:

Centripetal force on the end on the wind turbine is 2785.58 N

Explanation:

What is centripetal force:

Centripetal force is a type of force which tends an object or a body to move towards the center of the circle during when it is in circular motion.

Centripetal force is scientifically represented as : F=mω^{2} r

here,

F = Centripetal force

R = Radius

ω = angular velocity.

and as we all know π = 3.1415

Now let us take the values from the question,

mass(m)=3.8kgs

ω = 0.42 rev/s

now,  (0.42*2π) rad/s = 6.9639515449 rad/s

hence , by substituting the above values in the formula we get:

[tex]F=3.8(6.9639515449)^{2} (100)[/tex]

by solving the above equation we get

F = 2785.58 N

hence, the centripetal force on the following turbine is= 2785.58N.

To learn and know more about centripetal related problems click here:

https://brainly.com/question/79801

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