Answer :
There are 0.0824 moles of C atoms are present in a 2.0 g sample of caffeine (C₈H₁₀N₄O₂).
1 mole of caffeine (C₈H₁₀N₄O₂) → 8 moles of C
Molecular weight of caffeine (C₈H₁₀N₄O₂) = 8 (C) + 10 (H) + 4 (N) + 2 (O)
= 8 (12) + 10 (1) + 4 (14) + 2(16)
= 96 + 10 + 56 + 32
= 194 g of caffeine (C₈H₁₀N₄O₂)
194 g of caffeine (C₈H₁₀N₄O₂) → 8 moles of C
So, 2.0 g of caffeine (C₈H₁₀N₄O₂) → ? moles of C
∴ Moles of C = 2.0 g × 8 moles of C / 194 g
∴ Moles of C = 0.0824 moles
So, 0.0824 moles of C atoms are present in a 2.0 g sample of caffeine (C₈H₁₀N₄O₂).
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