suppose that 3\%3%3, percent of over 200{,}000200,000200, comma, 000 books borrowed from a library in a year are downloaded. the librarians plan to take an srs of 757575 books from the population of borrowed books to see what proportion of books sampled are downloaded.what are the mean and standard de



Answer :

In terms of the percentage of downloaded books, the sampling distribution's mean is 0.03 and its standard deviation is 0.0197.

Central Limit Theorem:

The sampling distribution of the sample percentage for a proportion p in a sample of size n will be roughly normal with a mean (μ = p) and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n} }[/tex].

In a given year, 3% of books checked out from the library are downloaded.

That means p = 0.03

and n = 75

By the Central Limit Theorem

Mean = μ = p = 0.03

Standard deviation =  [tex]s = \sqrt{\frac{p(1-p)}{n} }[/tex]

                                   [tex]s = \sqrt{\frac{(0.03)(0.97)}{75} }[/tex]

                                   [tex]s=0.0197[/tex]

Hence,

         In terms of the percentage of downloaded books, the sampling distribution's mean is 0.03 and its standard deviation is 0.0197.

Learn more about Central Limit Theorem here

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