into a jug after a party. the host then inserts a cork with a 2.00-cm diameter into the bottle, placing it in direct contact with the wine. the host is amazed when the host pounds the cork into place and the bottom of the jug (with a 14.0-cm diameter) breaks away. calculate the extra force exerted against the bottom if he pounded the cork with a 120-n force.

Question

15-12-2022
Physics

Answered

into a jug after a party. the host then inserts a cork with a 2.00-cm diameter into the bottle, placing it in direct contact with the wine. the host is amazed when the host pounds the cork into place and the bottom of the jug (with a 14.0-cm diameter) breaks away. calculate the extra force exerted against the bottom if he pounded the cork with a 120-n force.

Answer :

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Tutorconsortium434 Tutorconsortium434 · Answer 1 · 2022-12-21T04:30:21-05:00

The additional force F applied to the jug can be calculated as the cork's pressure P times the area of the bottom. P can be calculated simply dividing the force [tex]F_{1}[/tex] used on the cork according to its area [tex]A_{1}[/tex]

Describe pressure.

The force applied perpendicularly to an object's surface per unit area across which that force is dispersed is what we might refer to as pressure. The formula for calculating pressure is p = F/A, where F and A stand for force perpendicular to the surface and surface area, respectively.

What connection exists between pressure and force?

Pressure is determined by the formula pressure = force / area. As a result, a force exerted across a smaller area will result in more pressure.

Briefing:

[tex]F = PA_{2} = (F_{1} /A_{1} ) A_{2} = (14.00/2.00)^{2} (120) = 5880 N[/tex]

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