a golf ball of mass 0.050 kg is at rest on the tee and has a velocity of 102 m/s immediately after being struck. if the club and ball were in contact for 0.94 ms what is the average force exerted on the ball?



Answer :

A golf ball with a mass of 0.050 kg is at rest on the tee and accelerates to 102 m/s as soon as it is struck. The average force applied to the ball if the club and ball made contact for 0.94 ms is 6.3 kN.

Describe impulse.

Impulse is a term used to describe how a net force—a specific type of "moving force"—affects an object. An impulsive force is a strong force that acts quickly to cause a finite change in momentum. Impulsive forces were conceptualized separated from regular forces throughout science history.

How is impulse calculated in physics?

Force times time equals change in momentum for an impulse.

Briefing:

F = mv/t

F = (0.050 kg)(102 m/s) / 0.81 ms × 10⁻³ = 6.3 kN

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