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at one point in the pipe, the radius is 0.160 mm . what is the speed of the water at this point if the volume flow rate in the pipe is 1.20 m3/sm3/s .



Answer :

The flow rate of the water in the pipe is given by Q=Av

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

with the help of question,

,

Q=1.20m3/s

the radius of the pipe is

r = 0.160 m

So, the cross-sectional area is

;

;A=πr^2 where r=0.160mm

=π(0.160×0.160)2=0.0256m

So we can re-arrange the equation to find the speed of the water:

;v=Q/A=1.20m3/s/0.0256

=4687.5m3

To know more about area of pipe visit

https://brainly.com/question/19211820

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