Answer :
At 95% confidence interval for a sample of size 100 where p = 0.15 , the margin of error is 0.0700 .
In the question ,
it is given that ,
the sample size is = 100 and
the value of p is ⇒ 0.15 .
we have to find the "margin of error"(E) for the 95% confidence interval ,
we know that the z value for the 95% confidence interval is = 1.96
the formula for margin of error is :
E = Z×√p(1-p)/n .
Substituting the values of z , p and n ,
we get ,
E = 1.96×√0.15(1-0.15)/100
= 1.96×√0.15(0.85)/100
= 1.96×√0.1275/100
= 1.96×√0.001275
= 1.96×0.03570
Simplifying further ,
we get ,
= 0.06995899
rounding to the four decimal places ,
≈ 0.0700
Therefore , the required margin of error is 0.0700 .
The given question is incomplete , the complete question is
At 95% confidence, for a sample of size 100 where p = 0.15 . What is the Margin Of Error ? if required, round your answer to four decimal places.
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