Answer :
The nickel has a face-centered cubic (fcc) structure and has a density of 8.90 g/cm3. its atomic radius is 1.36 × 10⁻⁸ cm.
given that :
density = 8.90 g/ cm³
the density is given as :
density = mass / volume
no. of atoms = 8 (1/8) + 6(1/2)
volume = (r × 8 (1/8))³
mass = 4 atoms × mol / 6.022 × 10²³ atoms × 58.68 g /mol
density = mass / volume
8.90 g/ cm³ = (4 atoms × mol / 6.022 × 10²³ atoms × 58.68 g /mol ) / (r × 8 (1/8))³
r = 1.36 × 10⁻⁸ cm
Thus, the atomic radius is 1.36 × 10⁻⁸ cm.
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