a 2.50-m segment of wire supplying current to the motor of a submerged submarine carries 1000 a and feels a 4.00-n repulsive force from a parallel wire 5.00 cm away. what is the direction of the current in the other wire?



Answer :

The 400 A current flowing through the wire will be going the other way from the other wire.

What sort of force is repulsive?

An electroscope is a straightforward instrument that consists of a metal piece protruding from a glass jar with thin metal leaves suspended inside. This design demonstrates the electrostatic repulsive force. The leaves spread apart by the Coulomb force when a charged body touches the external metal piece.

We will apply the equation to determine the current in the other wire

F/l = µ₀I₁I₂/2πr and solve it for I₂.

The other wire's current will flow in the opposite direction to the first one because the force is repulsive.

I₂ = F.2πr/µ₀I₁l

I₂ = 4×2π×0.05m/4π×10⁻⁷T.m/A×1000A×2.50m

I₂ = 400 A.

The 400 A current flowing through the wire will be going the other way from the other wire.

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