a wire with mass 40.0 g is stretched so that its ends are tied down at points 80.0 cm apart. the wire vibrates in its fundamental mode with frequency 60.0 hz and with an amplitude at the antinodes of 0.300 cm. (a) what is the speed of propagation of transverse waves in the wire? (b) compute the tension in the wire. (c) find the maximum



Answer :

The speed of propagation of the transverse wave in the wire is 4800 cm/s. The tension in the wire is 15.71 N and the maximum transverse acceleration is 11,105,600 cm/s².

A transverse wave is a type of wave in which the particles of the medium move in a direction perpendicular to the direction of energy propagation. Examples of transverse waves include light, radio, and other types of electromagnetic waves.

The speed of propagation is the speed at which a signal travels through a medium, such as a wire, fiber optic cable, or radio wave.

(a) Speed of propagation of the transverse wave in the wire =

v = λf

= (80.0 cm) (60.0 Hz)

= 4800 cm/s

b)Tension in the wire = F/A

= m(ω² X A_max) / A

= (40.0 g)(2π² X 60²  X 0.300 cm²) / (80.0 cm)²

= 15.71 N

(c) Maximum transverse velocity = A_max X ω

= 0.300 cm X 2π X 60 Hz

= 1842.4 cm/s

Maximum transverse acceleration = A_max X ω²

= 0.300 cm X (2π X 60)²

= 11,105,600 cm/s²

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