Answer :
A genetic engineer was attempting to cross a tiger and a cheetah. she predicted a phenotypic outcome of the traits. According to the chi-square test, the ratio is 50 with stripes only, 41 with spots only and 85 with both. She got the predicted outcome.
Total number of individuals is N
So N = 50+41+85 = 176
The expected ratio of 176 individuals
4 stripes = 44 individuals
3 spots = 33 individuals
9 both = 99 individuals
Chi-square test,
X² = Σ (Observed -Expexted)² / Expected
So,
Stripes = 0.82
spots = 1.94
both spots and stripes= 1.98
Appling these values in the chi-square test
X² = 0.82 + 1.94 + 1.98 = 4.74
Degrees of freedom = n - 1
= 3 - 1
= 2
Significance level, 5% = 0.05
Table value/Critical value = 5.991
X² < CV
4.74 < 5.99
The difference between the observed and expected result is not very large. Mutation may be to blame for this.
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