a genetic engineer was attempting to cross a tiger and a cheetah. she predicted a phenotypic outcome of the traits she was observing to be in the following ratio 4 stripes only: 3 spots only: 9 both stripes and spots. when the cross was performed and she counted the individuals she found 50 with stripes only, 41 with spots only and 85 with both. according to the chi-square test, did she get the predicted outcome?



Answer :

A genetic engineer was attempting to cross a tiger and a cheetah. she predicted a phenotypic outcome of the traits. According to the chi-square test, the ratio is 50 with stripes only, 41 with spots only and 85 with both. She got the predicted outcome.

Total number of individuals is N

So N = 50+41+85 = 176

The expected ratio of 176 individuals

4 stripes = 44 individuals

3 spots = 33 individuals

9 both = 99 individuals

Chi-square test,

X² = Σ (Observed -Expexted)² / Expected

So,

Stripes = 0.82

spots = 1.94

both spots and stripes= 1.98

Appling these values in the chi-square test

X² = 0.82 + 1.94 + 1.98 = 4.74

Degrees of freedom = n - 1

                                  = 3 - 1

                                  = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.991

X² < CV

4.74 < 5.99

The difference between the observed and expected result is not very large. Mutation may be to blame for this.

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