Answered

a shopper in a supermarket pushes a loaded 37 kg cart with a horizontal force of 13 n. the acceleration of gravity is 9.81 m/s2 . a) disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m



Answer :

Tutorconsortium420

Answer:

The distance covered by the cart is 1.799 meters

Explanation:

The cart will accelerate as a result of the force being given to it, and the cart will move as a result of the acceleration. The equation can be used to determine the cart's acceleration-

a=F/m  (1)

the traveled distance can be found using the equation

s=ut+1/2at2              (2)

Given:

• Mass of the cart m=37 kg

• Force applied F=13 N

• Friction is negligible.

Since the friction is negligible all applied force will cause acceleration

Hence acceleration a=F/m=13/37≈0.3514 m/s2

When the cart was pushed it has initial velocity zero. Hence from question we have

• Initial velocity u=0

• Time t=3.2 s

• Acceleration a=0.3514 m/s2

Now using the 2nd equation we get the traveled distance

s=ut+1/2at2

s=0+1/2×0.3514×10.24

s≈1.799 m

To know more about force,

https://brainly.com/question/12785175

#SPJ4

Other Questions