Answered

a skater extends her arms horizontally, holding a 2 kg mass in each hand. she is rotating about a vertical axis with an angular velocity of 1 rev/s. if she pulls her hands in towards the center of her body, approximately what will the final angular velocity be if her own moment of inertia remains approximately constant at 5 kg m2, and the distance of the masses from the axis changes from 1 m to 0.2 m?



Answer :

The final angular velocity will be 10.96 rad/sec.

What are some instances of the law of conservation of angular momentum?

According to the rule of conservation of angular momentum, an object's angular momentum won't change when no external tension is applied to it. Several instances of momentum: The speed at which the Earth spins hasn't changed in billions of years.

How to solve the question?

Given, mass in each hand, m = 2 kg

        initial angular velocity, ω₁ = 1 rev/s = 1×2π = 6.28 rad/sec

        moment of inertia of skater, I = 5 kgm²

        initial distance of the masses from the axis, d₁ = 1m

        final distance of the masses from the axis, d₂ = 0.2m

    According to conservation of angular momentum,

 Linitial = Lfinal

 I₁ω₁ = I₂ω₂

I₁ = 5+2×2×1 = 9 kgm²

I₂ = 5+2×2×(0.2)² = 5.16 kgm²

9×6.283 = 5.16×ω₂

ω₂ = 9×6.2833/5.16

ω₂ = 10.96 rad/s

So, the final angular velocity will be 10.96 rad/s.

To know more about angular momentum visit

brainly.com/question/17370675

#SPJ4

Other Questions