what is the simplest formula of a solid containing a, b, and c atoms in a cubic lattice in which a atoms occupy two corners and one body-center position, the b atoms occupy two corners, and the c atoms occupy four corners and two faces of the unit cell?



Answer :

A solid with atoms a, b, and c arranged in a cubic lattice has the simplest formula possible: abc3.

Given that the unit cell's an atoms occupy two of its corners and one of its body centres, the b atoms occupy two corners, and the c atoms occupy four of its corners and two of its faces

There are eight corners, and each one has an atom in it.

Atomic number of a = 8 * 1/8 = 1

The centre b atom is the lone atom. So b = 1

Each of the six faces holds a c atom.

6 x 1/2 = 3 c atoms are present.

So when we combine them, we get the solid as abc3 formula.

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