what is the bond order for a second-period diatomic particle containing seven electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals?



Answer :

The Bond Order would be 0.5.

Bond order is the number of bonding pairs of electrons between two atoms. In a covalent bond between two atoms, a single bond has a bond order of one, a double bond has a bond order of two, a triple bond has a bond order of three, and so on.

Bond Order= [tex]\frac{Bonding E- Antibonding E}{2}[/tex]

so ,

= [tex]\frac{8-7}{2}[/tex]

= 0.5

As Bond Order is 0.5 so molecule would be very reactive as bond is pretty weak.

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