harding8495 harding8495

15-12-2022
Physics

Answered

next we move the q and 4q charges to be 3 times as far apart as they were: two charges, q and 4q, farther apart now what is the magnitude of the force on the 4q charge?

Answer :

Tutorconsortium417 Tutorconsortium417

23-12-2022

F"=4F/9 or F"=4F ÷9 is the magnitude for the force acting on the 4q charge.

Coulomb's law states that the magnitude of the forces between Q and 4Q is,

F'=КQ×4Q÷d²

= 4F ---------------------------(1)

Now, if the distance is made 3 times greater than before, or in three dimensions,

F''=КQ×4Q÷ (3d)²

Or F''= 4КQ² ÷ 9d²

or, F''= 4÷9 × ₍КQ²÷ d²₎

or, F''= 4F/9

Coulomb's law: a rule indicating that opposing charges attract and similar charges repel, with a force proportional to the product of the charges and inversely proportional to the square of the space between them.

Dimensions: an area that may be measured for its length, width, depth, or height.

To know more about magnitude visit this:

https://brainly.com/question/15681399

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