The volume of the gas at 321 K would be 2.69 Litres, if the volume of gas at 298 K is 2.5 L
Since the pressure depends on the number of moles, it will remain constant and rest of formula is
[tex]\frac{Volume_{Intial} }{temperature_{inital}}[/tex] = [tex]\frac{Volume_{Final} }{temperature_{final} }[/tex]
which on cross multiplying becomes :
Volume(f) = (Volume(i) X temperature(f)) / temperature(i)
Volume = (2.5 * 321) / 298 = 2.69 Liters
To learn more about Volume-Temperature Relation :
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