if the reaction yields 21.1l of nitrogen gas what mass of nan3 in grams would be required to produce this volume at stp?

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15-12-2022
Chemistry

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if the reaction yields 21.1l of nitrogen gas what mass of nan3 in grams would be required to produce this volume at stp?

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jaspreetsharma jaspreetsharma · Answer 1 · 2022-12-25T00:15:31-05:00

if the reaction yields 21.1l of nitrogen gas, 40.81g mass of nan3 in grams would be required to produce this volume at stp

mass of NaN3 (g) = moles of NaN3 (ma) x molar mass of Na N3 (g/mol) = 0-678 mol 65 g/mol =40.81g. A chemical compound's molar mass is described as the weight of a sample of that chemical divided by the quantity of substance in that sample, which is the quantity of moles in that sample, evaluated in moles. The molar mass of a substance is a mass property, not a molecular property. It is the connection between pressure, volume, moles, and temperature. is the volume that one mole of the a chemical substance or a chemical compound takes up. As a result, at STP, the molar volume of a gas is 22.4 litres.

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