Answer :
When the gauge pressure of the helium is 0.350 atm, the internal energy of the gas is 1.35 times higher.
We may apply the equation of internal energy for ideal gases since the helium in the balloon is an ideal gas.
where p represents pressure is 1.350atm.
The volume is V it is 11.0L, and the number of moles is n.
The gas constant is R.
T is the gas's actual temperature 1.350 * 11 /nR = 14.85 /nR.
Here are the details for the internal energy helium gas in the balloon:
(The gauge pressure and ambient pressure add up to the total pressure.) is the amplitude
Thus, the temperature may be expressed as 11/nR
Instead, we have what is known as the helium balloon's zero gauge pressure (i.e., at atmospheric pressure).
Between the two temperatures, there is a ratio of 14.85/11 = 1.350
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