0.50 mol SO₂ and 0.50 mol O2 to a 1.00 liter flask. at equilibrium, 0.35 moles of SO₃ in the flask. the value for the equilibrium constant (Kc) for the reaction is 5.55
the chemical reaction is given as :
2SO₂(g) + O₂(g) ⇄ 2SO₃(g)
The equilibrium constant is defined as the ratio of the amount of the product to the amount of the reactant. at equilibrium the rate of forward reaction is equals to the rate of the backward reaction.
the expression for equilibrium constant is given as follows :
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.50)² / (0.50) / (0.3)²
Kc = 5.55
Thus, the equilibrium constant for the reaction is 5.55.
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