a compound was analyzed and was found to contain the following percentages of the elements by mass: barium, 89.56%; oxygen, 10.44%. determine the empirical formula of the compound.



Answer :

The empirical formula of the compound is BaO₅

What is empirical formula?

the empirical formulate of a chemical compounds is the simple whole numbers ratio of the  atoms present in the  compound.

We have to determine the empirical formula of an compound that contains the following percentages by mass: O=10.44 %; % Ba=89.56%;

Empirical formula shows simplest whole number ratio of atoms in compound.

We have to find the simplest ratio of O and Ba. using ratio of percentages and atomic masses.

Atomic masses are known from periodic table: ArAr(O)=32 g/mol ArAr(Ba)= 137.3g/mol

N(O):N(Ba)= %O/Ar(O):%Ba/Ar(Ba)

N(O):N(Ba)=10.44%/32: 89.56%/137.3

N(O):N(Ba)= 0.32625:0.65229

Now we have to devide with smallest number

N(O):N(Ba)=0.32625:0.65229/0.65229

N(O):N(Ba)=5:1

The empirical formula is BaO₅

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