the half-life of methyl mercury in the body is 70 days. how many days are required for the amount of methyl mercury to drop to 10% of the original value after accidental ingestion.



Answer :

233 day are required for the amount of methyl mercury to drop to 10% of the original value after accidental ingestion.

What is methyl mercury?

An organometallic cation with the formulation [CH3Hg]+ is methylmercury. The simplest organisers  compound is this 1. Because of its highest toxicity, methylmercury is the main source of organic mercury for humans. It is an environmentally harmful bioaccumulative substance's.

For a first order reactions, (1/2)number of half-lives = the decimal amount remaining

Remaining amounts of methylmercury = 0.10

(½)n = 0.10; n = number of half-life

n log1/2 = log 0.10

n = -1/-0.3010 = 3.32

days required is  = 3.32 time

The  half life = 3.32 x 70 = 233 day.

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