a candle that is 10.0 cm high is placed 30.0 cm in front of a diverging lense the lens has a focal length of -20.0 cm what is the magnification of the image



Answer :

The magnification of the image is 0.4cm.

What is magnification?

Magnification is the processes of enlarging to the apparently sizes, not physical sizes, of something's. This enlargements is quantifies by a calculates numbers also called "magnifications".

Height of the object= 10cm

Focal length of the lens is f=20 cm

Here we are using the formula

1/v-1/u = 1/f

Where v be the position of the image and u be the position of the object.

Here we take all the distances with negative sign.

Which is the front of delivering lens and with posetive sign which is behind the lens that is:

u=-30cm

f=-20cm

then,

1/v-1/-30=1/-20

1/v= -1/30-1/20

v=-12cm

negative sign shown that image is in front side of the lens

magnification of the image is

m=v/u

m=-12/-30

m=0.4 cm.

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