25.00 ml of an unknown concentration of acetic acid is titrated with 40.62 ml of the standard base (use molarity from 9 above). what is the molarity of this acid? (hint: example 12.4

Question

15-12-2022
Chemistry

Answered

25.00 ml of an unknown concentration of acetic acid is titrated with 40.62 ml of the standard base (use molarity from 9 above). what is the molarity of this acid? (hint: example 12.4

Answer :

Other Questions

What is the ph of a buffer made of 2.00 m acetic acid ch3cooh and 2.00 m sodium acetate nach3coo? [hint: use the henderson hasselbalch equation: ph = pka + log

A student is asked to standardize a solution of calcium hydroxide. he weighs out 0.990 g potassium hydrogen phthalate (khc8h4o4, treat this as a monoprotic acid

A 50.0-ml sample of 0.200 m hcl is titrated with 0.200 m naoh. calculate the ph: a. when no base is added b. after adding 30.00 ml of naoh c. at the. equivalenc

using an acetic acid sodium acetate buffer what ratio of acid to conjugate base will you need to maintain the ph at 5

10.00 g calcium carbonate (found in limestone) was dissolved in 100.0 ml hydrochloric acid (d = 1.148 g/ml) . the products were 120.40 g solution (a mixture of

The calcium from a 5.00 g sample of tomato paste was extracted into acid and brought to a final volume of 250.0 ml. the ca2+ concentration of this extract was 6

the titration of 0.5541 g of khp required 25.86 ml of an naoh solution to reach the equivalence point. what is the concentration of the naoh solution?

What mass of NaNO3 would be needed to make a saturated solution in 200 mL of water at 80°C?

You now need to make 150 mL of a 1 mg/mL hemoglobin solution. How many mg will you need? Your scale measures mass in grams. How many grams of hemoglobin will yo

rekharaypriti8910 rekharaypriti8910 · Answer 1 · 2022-12-24T03:58:43-05:00

If 34.57 mL of a solution of acetic acid are required to neutralise 25.19 mL of sodium hydroxide with a 0.1025 M concentration, determine the molarity of the solution.

The amount of acetic acid in moles per solution liter is known as the molarity. The mass of the solution divided by the density gives the area of the mixture. Subtract the amount of the analyte from the amount of moles of the analyte that are present. For instance, if the analyte's initial volume were 500 mL, divide that by 1000 mL / L to get 0.5 L. To get 0.02 moles per liter, divide 0.01 mole of analyte by 0.5 L. This is the molarity or concentration. The typical equation is C = m/V, in which C is the percentage, m is the weight of the drop wise, as well as V seems to be the total amount of the solute.

Learn more about acids

https://brainly.com/question/29426933

#SPJ4