0.1218 M is the molarity of the solution
mole of Ca(oH)2 == mass/ molar mass
= 4.152/74.053
=0.060 g. mol
volume of the solution= 500ml
=500/1000
= 0.5 L
Molarity= mole/ litre
= 0.060 g mol/ 0.5L
= o.1218 M
The amount of a solute per unit volume of solution is how much a chemical entity is present in a solution, and this is known as its molar concentration. "The molarity of products is divided by the molarity of reactants" is the formula for determining an equilibrium constant.
in a experiment similar to yours, a solution is prepared by adding 4.512 g of slaked lime also known as calcium hydroxide to 500.00 ml of water. a. what is the molarity of the solution
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