Answer :
The minimum distance required by the car to stop a 62.5 m.
The mass of the car is given to be 1000 kg and it is travelling at a speed of 20 the brakes are applied by the car that is producing force of 5000 Newton.
Firstly the negative acceleration produced in the car will be,
F = Ma
M is the mass of the car,
F is the force appoint by the brakes and,
a is the negative acceleration.
Putting values,
5000 = 1000(a)
a = 5m/s².
So, the negative acceleration produced by the brakes is 5m/s².
The minimum distance required by the car to stop will be given by other relation,
D = U²/2a
Where, U is the initial speed of the car,
Putting values,
D = 25×25/2×5
D = 62.5m.
So, the stopping distance of the car will be 62.5 m.
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