2. suppose that a 1000 kg car is traveling at 25 m/s (55 mph). its brakes can apply a force of 5000 n. what is the minimum distance required for the car to stop?



Answer :

The minimum distance required by the car to stop a 62.5 m.

The mass of the car is given to be 1000 kg and it is travelling at a speed of 20 the brakes are applied by the car that is producing force of 5000 Newton.

Firstly the negative acceleration produced in the car will be,

F = Ma

M is the mass of the car,

F is the force appoint by the brakes and,

a is the negative acceleration.

Putting values,

5000 = 1000(a)

a = 5m/s².

So, the negative acceleration produced by the brakes is 5m/s².

The minimum distance required by the car to stop will be given by other relation,

D = U²/2a

Where, U is the initial speed of the car,

Putting values,

D = 25×25/2×5

D = 62.5m.

So, the stopping distance of the car will be 62.5 m.

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