Answer :
It is false that a helium atom fusing with a hydrogen atom is the initial stage in the hydrogen-burning process.
Four hydrogen protons and two electrons are used in the basic hydrogen fusion cycle, which results in the creation of a helium nucleus, two neutrinos, and six photons. The first stage in this three-phase process is the fusion of hydrogen into deuterium. In this collision of two protons, one proton decays into a neutron, which releases an antielectron and a neutrino.
The last proton joins the neutron to form a heavy hydrogen (deuterium) nucleus, and the newly created antielectron will annihilate with an electron to generate two very high-energy photons.
A proton is grabbed by a deuterium nucleus, which subsequently emits a photon and forms a 3He nucleus, in the second phase of the synthesis of helium-3.
The third phase involves recombining two helium-3 atoms into a single helium nucleus while emitting two protons.
Take note that for every time step 3 happens, steps 1 and 2 each occur twice. The total net energy released during this process is 26 MeV.
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