how many full spectral orders can be seen (400 to 700 nm ) on each side of the central maximum when it is illuminated by white light?



Answer :

When central maximum is illuminated by white light, then six(6) full spectral orders can be seen on each side.

For calculating this we need to know the wavelength of white light when visible light wavelength is in range of 400 to 700nm.

Now, we know that dsinθ=mλ

where d is the distance between slits,

λ is the wavelength

sinθ is the angle made by light with medium

and m is the ratio of wavelength

Firstly, we assign sinθ=1

=>m=d/λ----------eq1

For finding d, we know that d=1/granting

=>d=1/(400×10⁹)

=>d=2.5 ˣ 10⁻⁶m

Now, we know that for finding m we need to put value in eq1

At 400nm wavelength, we get

=>m=2.5 ˣ 10⁻⁶m/400ˣ10⁹m

=>m=6.25

At 700nm wavelength, we get

=>m=2.5 ˣ 10⁻⁶m/700ˣ10⁹m

=>m=3.17

Now, we know that fourth maxima value is 3.17 and seventh maxima value is 6.25

It means there are three maxima in between seventh and fourth maxima.

Total number of maxima on both sides =3ˣ2=6

Hence,6 full spectral orders can be seen.

To know more about central maximum ,visit here:

https://brainly.com/question/16217819

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