an object is located in air 26 cm from the vertex of a concave surface made of glass with a radius of curvature 12cm. where does the image by refraction form? use nair



Answer :

If the object is located in air 26 cm form the vertex of concave mirror , then the image by refraction is formed at  18.087  cm .

The relation between the object distance(u) , image distance(v) , the radius of curvature (r) and the refractive index of the mediums (n₁ and n₂) is :

n₂/v - n₁/u = (n₂ - n₁)/R

it is given that ,object is located at a distance of 26 cm , that is , u = 26 cm  .

the radius of curvature of the concave surface is = 12 cm ,

we know that the refractive index ([tex]n_{air}[/tex] = 1 and [tex]n_{glass}[/tex] = 1.6) ;

Substituting the values ,

we get ;

1.6/v - (-1/26) = (1.6 - 1)/(-12)

1.6/v + 0.03846 = -0.05 ;

1.6/v = -0.05 - 0.03846

1.6/v = -0.08846

v = -1.6/0.08846

v = -18.087 cm .

Therefore , the image by refraction is formed at 18.087 cm .

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