Answer :
If the object is located in air 26 cm form the vertex of concave mirror , then the image by refraction is formed at 18.087 cm .
The relation between the object distance(u) , image distance(v) , the radius of curvature (r) and the refractive index of the mediums (n₁ and n₂) is :
n₂/v - n₁/u = (n₂ - n₁)/R
it is given that ,object is located at a distance of 26 cm , that is , u = 26 cm .
the radius of curvature of the concave surface is = 12 cm ,
we know that the refractive index ([tex]n_{air}[/tex] = 1 and [tex]n_{glass}[/tex] = 1.6) ;
Substituting the values ,
we get ;
1.6/v - (-1/26) = (1.6 - 1)/(-12)
1.6/v + 0.03846 = -0.05 ;
1.6/v = -0.05 - 0.03846
1.6/v = -0.08846
v = -1.6/0.08846
v = -18.087 cm .
Therefore , the image by refraction is formed at 18.087 cm .
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