determine the force of gravitational attraction between the earth and a 62.0 kg physics student if the student is standing at sea level.



Answer :

The force of gravitation attraction between the earth and the physics student is 607.6 N   .

The Force of Gravitation is defined as force of attraction that arises between two bodies that have definite mass .

given that the mass of the physics student is 62 Kg ;

we know that , F = GmM/d²

where , G = 6.67 × 10⁻¹¹ Nm²/Kg²  ,

mass of earth ⇒ 5.98 × 10²⁴ Kg , mass of student ⇒ 62 Kg ,

distance of separation ⇒ 6.38 × 10⁶ m;

So , the force is = (6.67×10⁻¹¹ × 5.98×10²⁴ × 62)/(6.38×10⁶)²

F = (2472.9692×10¹³)/(40.7044 × 10¹²)

Simplifying further ,

we get ;

F = 607.543 N

F ≈ 607.6 N

Therefore , the force of gravitational attraction is 607.6 N  .

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