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a chemist needs 900ml of a 40% acid solution for a chemistry experiment. the chemist combines x ml of a 20% acid solution, and y ml of a 70% acid solution to make the 40% acid solution. how many ml of the 20% acid solution and the 70% acid solution are combined to make the 40% acid solution?



Answer :

pstnonsonjoku

360 ml of the 70% acid and 540 ml of the 20% acid is required to make the 40% acid.

What is the volume combined?

We know that this is a mixture problem thus we would have to apply the algebra of the problem so as to obtain the required solution. We are told that; The chemist combines x ml of a 20% acid solution, and y ml of a 70% acid solution to make the 40% acid solution.

We would then set up a pair of equations as follows;

x + y= 900...........eq 1

0.2x + 0.7y= 0.4(900)...eq 2

x = 900 - y ------ eq 3

Then;

0.2( 900 - y) + 0.7y = 360

180 - 0.2 y + 0.7y = 360

0.5 y = 180

y = 360 ml

Then we have;

x + 360 = 900

x = 540 ml

These are the required volumes.

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