The number of times that 9 go into 28 is 3 times with a remainder of 1.
Given the divisor and dividend in the question;
28 ÷ 9
Set up the division problem in a long division format
divisor Γdividend
9Γ28
Divide 28 by 9, place the digit in the quotient on top of the division symbol.
3
9Γ28
Multiply the newest quotient digit (3 )by the divisor (9)
3
9Γ28
27
Subtract 27 from 28
3
9Γ28
27
----------
1
Therefore, the result of the division is 3 with a remainder o 1.
Learn more about long division here: https://brainly.com/question/28824872
#SPJ1