A boy standing on a bridge drops a rock from the top of the bridge. If the top of the bridge is about 64.0 m high above the surface of water, how long does the rock take to hit the surface of water ? Ignore air resistance.



Answer :

The rock will take 3.61 seconds to hit the surface of the water.

What is the equation of motion?

The equations of motion can be described as the equation that described the relationship between the velocity (v & u), acceleration, time, and displacement (S) of a moving body.

The mathematical  expression of the equations of motion:

[tex]v = u +at\\S = ut +(1/2)at^2\\v^2-u^2 = 2aS[/tex]

Given, the height of the bridge from the ground, h = 64.0 m

The gravitational acceleration on the rock, g = 9.8 m/s²

The initial speed of the rock, u = 0

From the 2nd equation of motion, calculate the time rock takes to hit the surface of the water:

h = ut + (1/2)gt²

64.0 = 0×t + (1/2)× 9.8×t²

t² = 64 ×2/9.8

t = 3.61 s

Learn more about the equation of motion, here:

brainly.com/question/16982759

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