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Three people are selected from a group of fifteen men and seven women. Find the following probabilities. (Round your answers to three decimal places) (a) All three are men. (b) The first two are women and the third is a man



Answer :

Part a: probability (all men) =  13/44.

Part b: probability that first two are women and the third is a man is 3/44.

Explain the term permutation?

  • The amount of possible arrangements for a given set is calculated computationally, and this is referred to as permutation.
  • Simply said, a permutation is a term that applies to the variety of possible arrangements or orders.

For the stated question;

  • Total men M = 15
  • Total women W = 7
  • Total member = 22

Three member are selected.

probability = favourable outcome/Total outcome

Part a: probability that all are men.

P(3M) = (15/22) x (14/21) x (13/20)

P(3M) = 13/44

Part b: probability (first two are women) and the third is a man.

P(2W + 1M) = (7/22) x (6/21) x (15/20)

P(2W + 1M) = 3/44

Thus, probability that first two are women and the third is a man is 3/44.

To know more about the permutation, here

https://brainly.com/question/1216161

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