A manufacturer finds that the revenue generated by selling x units of a certain commodity is given by the function R(x)=80x-0.4x2, where the R(x) is measured in dollars. What is the maximum revenue, and how many units should be manufactured to obtain this maximum?



Answer :

The maximum revenue is $4,000 and 100 units should be manufactured to obtain the maximum revenue.

How to calculate a maximum of a function?

The maximums of a function are detected when the derivative becomes null and changes its sign (passing through 0 from the positive side to the negative side).

According to the given question:

Given function is

r(x) = 80x - 0.4x²

where the revenue r(x) is in dollar and no. unit is x.

We know that if function

y = ax²+bx+c.

Then we get the maximum value of y when x = -b/2a

Here a= -0.4 , b = 80 and c = 0.

Therefore,

x = -80/(2*-0.4)

x = 100

Therefore we get maximum revenue when x = 100.

∴ r(100) = 80.100- 0.4(100)²

             =$4000

Therefore the maximum revenue is $4,000 and 100 units should be manufactured to obtain the maximum revenue.

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