in your chemistry class, you have a bottle of 5% boric acid solution and a bottle of 2% boric acid solution. you need 60 milliliters of a 3% boric acid solution for an experiment. how much of each solution do you need to mix together? use x and y as your variables.

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12-12-2022
Mathematics

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in your chemistry class, you have a bottle of 5% boric acid solution and a bottle of 2% boric acid solution. you need 60 milliliters of a 3% boric acid solution for an experiment. how much of each solution do you need to mix together? use x and y as your variables.

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In order to achieve the desired 3% boric acid solution, the 5% and 2% boric acid solutions must be combined. To do this, we will use the following equation:

Volume of 5% solution (x) + Volume of 2% solution (y) = 60 mL

3x + 2y = 60

To solve for x and y, we will use the substitution method. We will start by solving for y first.

2y = 60 - 3x
y = (60 - 3x) / 2

Now that we have y, we can substitute it into the original equation.

3x + 2(60 - 3x) = 60
3x + 120 - 6x = 60
3x - 6x = 60 - 120
-3x = -60
x = 20

Finally, we can substitute x back into the equation for y to find our final answer.

y = (60 - 3(20)) / 2
y = (60 - 60) / 2
y = 0

Therefore, you will need 20 mL of 5% boric acid solution and 0 mL of 2% boric.

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