Part 1: The mean number of orders are 1.4 and Part 2: The probability of receiving at least 3 orders is 0.1665.
An average of n numbers computed by adding some function of the numbers and dividing by some function of n. synonyms: mean. types: arithmetic mean, expectation, expected value, first moment. the sum of the values of a random variable divided by the number of values.
1) Here 7 orders per 600 solicitations,
So in 120 solicitations,
=7/600 x 120
=1.4
2) P(x>3)= 1-P(x< 2)
=1-e^-1.4 (1.4^0/0+1.4^1/1+1.1^2/2)
=0.1665
The probability is 0.1665.
To learn more about probability check the link below:
https://brainly.com/question/24756209
#SPJ4